Continuity

at a point

A function f:𝒟 is continuous at ω if

  1. f is defined at ω i.e., ω𝒟;
  2. limxω f(x) exists;
  3. limxω f(x) =f(ω) .

One sided

Right continuous
limxω+ f(x) = f(ω)
Left continuous
limxω- f(x) = f(ω)

on interval

A function is continuous on an interval if it is continuous at every point in

Continuity properties

  • 𝒶 f(x) ± 𝒷 g(x)
  • f(x) g(x)
  • f(x) g(x) when defined
  • f(x) n for n+
  • f(x) n , n+ when defined

Polynomial and rational functions are continuous on their domain.

Trigonometric functions are continuous on their domains.

Inverse functions of continuous functions are continuous on their domain.

Discontinuities

removable
limxω f(x)
jump

limxω+ f(x) , limxω- f(x) and limxω+ f(x) limxω- f(x)

Functions with removable discontinuities have continuous extensions.

Discontinuities

infinite
lim xω+ f(x) =± or limxω- f(x) =±
oscillating
lim xω f(x) approaches more than one value

Explanations and Examples

Find the interval of continuity

  • f1 (x) = x-1 x2 +2x
  • f2 (x) = x2 +2x -5
  • f3 (x) = sin ( x2 -4 )

Evaluate the limits

  • limx π2 cos ( 2x +sin ( 3π 2 +x ) )
  • limx0 x+1 tanx

Show that p(x) =x3 +3x2 +x -1 has a root between zero and one.

Let f(x) = |x| x , then f(-3) =1 and f(2) =1, does that the Intermediate Value Theorem imply there is a root between negative three and two?

Implications

Composition of continuous functions

If f is continuous at ω and g is continuous at f(ω) then fg is continuous at ω

If lim xω f(x) =𝓁 and g(x) is continuous at 𝓁 then

limxω g (f(x) ) = g ( limxω f(x) )

Intermediate value theorem

Let f(x) be continuous on an interval [a,b] then.

ν ( 𝓂, ) , ω (a,b) : f(ω)=ν

where

  • 𝓂 = min ( f(a) , f(b) ) , and
  • = max ( f(a) , f(b) )