Volume

Cross sections

Volume = area × height

integrable cross sections

Volume of a solid of integrable cross-sectional area 𝒜(x) from x=𝒶 to x=𝒷 is

𝒱= 𝒶 𝒷 𝒜(x) dx

integrable cross sections

  1. Sketch the solid and typical cross section region.
  2. Formulate the area function 𝒜(x).
  3. Find the limits of integration.
  4. Evaluate the integral.

pyramid

Find the volume of a pyramid with height 12 and base 6.

wedge

A curved wedge is cut from a circular cylinder of radius three by two planes. One plane is perpendicular to the axis of the cylinder and the other forms a π4 angle with the first one at the center of the cylinder. Find the volume of the wedge.

solid

Find the volume of a solid with base the region between the functions f(x) =x2-1 and g(x) =-x2+1 . Its cross sections perpendicular to the x-axis are equilateral triangles.

Solids of Revolution

slices

𝒱 = 𝓁 𝓊 𝒜 d = 𝒶 𝒷 π ( (x) ) 2 dx = 𝒸 𝒹 π ( (y) ) 2 dy

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= x2 -4x +5 , x=1 and x=4 rotated around the x-axis.

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= x , from x=0 to x=4 rotated around the x-axis.

Find the volume of the solid of revolution formed by revolving region bounded by g(y)= 4-y and the y-axis over the y-interval [0,4].

Solids of Revolution

slices

Washer method

𝒱 = 𝓁 𝓊 𝒜 d = 𝒶 𝒷 π ( [ (x) ] 2 - [𝓇 (x) ] 2 ) dx = 𝒸 𝒹 π ( [ (y) ] 2 - [𝓇 (y) ] 2 ) dy

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= x and g(x)= 1 rotated around the x-axis over the x-interval [1,4].

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= x and g(x)= 1x rotated around the x-axis over the x-interval [1,4].

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= 4-x and the x-axis rotated around the line y=-2 over the x-interval [0,4].

Solids of Revolution

Cylindrical shells

𝒱 = 𝓁 𝓊 d𝒜 = 𝒶 𝒷 [f(x)] [ 2πx dx ] = 𝒶 𝒷 2πx f(x) dx = 𝒸 𝒹 [g(y)] [ 2πy dy ] = 𝒸 𝒹 2πy g(y) dy

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= x+1 and g(x)= (x-1) 2 rotated around the y-axis.

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= -x3 +2x2 in the first quadrant rotated around the y-axis.

Find the volume of the solid of revolution formed by revolving region bounded by f(x)= x , from x=0 to x=4 rotated around the x-axis.

Find the volume of the solid of revolution formed by revolving region bounded by g(y)= 4-y and the y-axis over the y-interval [0,4].