in ℝ3

ℒ= (-764-322-331) p(x) = det( xℐ3 -ℒ ) = 2+5⁢x+4⁢x2+x3 = (x+2)⁢(x+1)2

Eigenvalue λ1=-2

(5-6-403-4-203-3-30) → (10-2001-100000)

Eigenvalue λ2=-1

(6-6-403-3-203-3-20) → (3-3-2000000000)